For nA = 2 mol and nB = 3 mol, what is the mole fraction xA?

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Multiple Choice

For nA = 2 mol and nB = 3 mol, what is the mole fraction xA?

Explanation:
Mole fractions describe the proportion of moles of each component in a mixture. For a mixture with two components, x_A is the number of moles of A divided by the total moles: x_A = n_A / (n_A + n_B). With n_A = 2 mol and n_B = 3 mol, the total is 5 mol, so x_A = 2 / 5 = 0.4. This means forty percent of the moles in the mixture are A. The other values correspond to different distributions: 0.50 would require A to be half of the total moles, 0.20 would require A to be one-fifth of the total, and 0.60 would require A to be three-fifths of the total.

Mole fractions describe the proportion of moles of each component in a mixture. For a mixture with two components, x_A is the number of moles of A divided by the total moles: x_A = n_A / (n_A + n_B).

With n_A = 2 mol and n_B = 3 mol, the total is 5 mol, so x_A = 2 / 5 = 0.4. This means forty percent of the moles in the mixture are A.

The other values correspond to different distributions: 0.50 would require A to be half of the total moles, 0.20 would require A to be one-fifth of the total, and 0.60 would require A to be three-fifths of the total.

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